R(p)=-9p^2+900

Solution for R(p)=-9p^2+900 equation:

(R)=-9R^2+900

We move all terms to the left:

(R)-(-9R^2+900)=0

We get rid of parentheses

9R^2+R-900=0

a = 9; b = 1; c = -900;
Δ = b2-4ac
Δ = 12-4·9·(-900)
Δ = 32401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{32401}}{2*9}=\frac{-1-\sqrt{32401}}{18}
$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{32401}}{2*9}=\frac{-1+\sqrt{32401}}{18}
$